Math, asked by swatishankar, 4 months ago

if tan tita = 12upon5,then find 1+ sin tita upon 1-sin tita

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Answered by Mrvagh151

Ask Question CBSE - if sin 3 tita / sin tita =11/ 25 then tan tita / 2 has balue equal ... {2 * sin θ * cos2 θ + (1 - 2 * sin2 θ) * sin θ}/sin θ = 11/25.

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if tan tita = 12upon5,then find 1+ sin tita upon 1-sin tita​

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if tan tita = 12upon5,then find 1+ sin tita upon 1-sin tita