Question

if tan tita =√3 find the value of (2sec tita /1+tan2 tita )​

Answer 1

Answer:

$tanx \: = \sqrt{3} \\\ \frac{2secx}{1 + {tan}^{2} x} \\ = \frac{2tanx}{ {tan}^{2} x} \\ = \frac{2}{tanx} \\ = 2cotx \\ = 2 \times \frac{1}{ \sqrt{3} } \\ = \frac{2}{ \sqrt{3} }$