Question

if tan tita = a/b then. a sin tita - b cos tita /a sin tita + b cos tita ?​

Answer 1

$\huge \mathfrak \purple{answer : } \\ \sf \green{tan \theta = \frac{a}{b} = \frac{sin \theta}{cos \theta} } \\ \sf \red{ \frac{asin \theta - bcos \theta}{asin \theta + bcos \theta} } \\ \sf \green{ \frac{a \times a - b \times b}{a \times a + b \times b} } \\ \sf \green{ \boxed{\frac{ {a}^{2} - {b}^{2} }{ {a}^{2} + {b}^{2} } } }$

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