Math, asked by Aarav46600, 6 months ago

If tan x = -2 , find the value of sin x ( x lies in the II Quadrant). Ans With Steps

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Answered by Anonymous
0

Answer:

tanx = -2

X lies in the 2nd Quadrant.

In the 2nd quadrant, sine and cosec are positive. Hence, we know that

tanx = -2/1

sinx =

 \frac{ - 2}{ \sqrt{ { - 2}^{2}  +  {1}^{2} } }

=

 \frac{ - 2}{4 - 1}

= -2/3.

However sine X is positive in the 2nd quadrant. Hence the answer is 2/3.

Answered by DEADPOOLAadi18
2

Answer:

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