if tan x =2 tan y, then find sin(x+y) /sin(x-y) =3
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Answer:
We have, tanx+tany=sinxcosx+sinycosy,
=sinxcosy+cosxsinycosxcosy,
⇒tanx+tany=sin(x+y)cosxcosy...................(□1).
Similarly, tanx−tany=sin(x−y)cosxcosy............(□2).
∴ by (□1)and(□2),tanx+tanytanx−tany,
=sin(x+y)sin(x−y).
Hence, the Proof.
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Steve M
Mar 16, 2018
We seek to prove that:
sin(x+y)sin(x−y)≡tanx+tany
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thanks
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