Question

If
tan (x^2)then find dy/dx
​

Answer 1

Explanation:

d(tanx)/dx = sec²x

By using chain rule

d(tanx²)/dx = sec²x².2x.1

=2xsec²x²

Answer 2

Given that ,

The function is Tan(x²)

Differentiating with respect to x , we get

$\rm \mapsto \frac{dy}{dx} = \frac{d \{Tan {(x}^{2} ) \}}{dx} \\ \\\rm \mapsto \frac{dy}{dx} = {Sec}^{2} ( {x}^{2}) \frac{d {(x)}^{2} }{dx} \\ \\\rm \mapsto \frac{dy}{dx} =2x. {Sec}^{2} ( {x}^{2})$

Remmember :

$\sf \hookrightarrow\frac{dTan(x)}{dx} = {Sec}^{2} (x) \\ \\ \sf \hookrightarrow \frac{d {(x)}^{n} }{dx} = n {(x)}^{n - 1}$