If tan x = (2t * (t + 1))/(2t + 1) find sinx and cosx
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sinx=1+t22t
Differentiate both sides w.r.t. t
cosxdtdx=(1+t2)2(1+t2)(2)−2t(0+2t)
cosxdtdx=(1+t2)22+2t2−4t2
cosxdtdx=(1+t2)22−2t2
dtdx=(1+t2)22(1−t2)×(1+t2)2−4t21+t
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