if tan x=-4/3 and x is not in the second quadrant then find 5 sin x+10cos x+9sec x+16cosec x+4cot x
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first of all the angle is in 4th quadrant
secondly opposite/adjacent is 4/3
take opposite as 4& adjacent as 3
thirdly find out hypotenuse (u may be getting 5)
substitute the ratio of sides to its corresponding trigonometric ratios
and apply sign convention (4th quadrant has cos&secx positive and rest all are negative)
you may get the answer dude
secondly opposite/adjacent is 4/3
take opposite as 4& adjacent as 3
thirdly find out hypotenuse (u may be getting 5)
substitute the ratio of sides to its corresponding trigonometric ratios
and apply sign convention (4th quadrant has cos&secx positive and rest all are negative)
you may get the answer dude
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