Question

If tan x = 4/3 find the value f 4sin²x-3cos²x+2​

Answer 1

Answer:

87/25

Step-by-step explanation:

(secx)^2 = 1 + (tanx)^2 = 1 + (4/3)^2

(secx)^2 = 1 + 16/9 =25/9

cos²x = 1/(secx)^2 = 9/25

4sin²x-3cos²x+2

= cos²x { 4(tanx)^2 -3 +2(secx)^2 }

= (9/25) { 4×(16/9) -3 + 2×(25/9) }

= (9/25) { 64/9 + 50/9 -3 }

= (9/25) { 114/9 -3 }

= (9/25) (87/9}

= 87/25