if tan x =5/12,then find sec x
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Answered by
104
Tanx = 5 / 12
From above we can say that in a right angled triangle
Opposite side = 5
Adjacent side = 12
Hypotenuse side = sqrt(5^2 + 12^2) = 13
Sec x = Hypotenuse side / Adjacent side
Sec x = 13 / 12
From above we can say that in a right angled triangle
Opposite side = 5
Adjacent side = 12
Hypotenuse side = sqrt(5^2 + 12^2) = 13
Sec x = Hypotenuse side / Adjacent side
Sec x = 13 / 12
Answered by
70
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