if tan x=8/3, find sin x=?
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Answered by
2
tan x = 8/3 = p/b
hence p =8 and b =3
find h by Pythagoras theorem...
h= √psq + bsq
h = √64+9
h = √73
sin x = p / h = 8/√73
hope it helps you
Anonymous:
good job
Answered by
1
sinx = tanx * cosx
= tanx / secx
= tanx / √(tan^2x +1)
= (8/3) / √(64/9 + 1)
= (8/3) / √(73/9)
= 8 / √73 Ans....
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