Question

if tan x=8/3, find sin x=?​

Answer 1

tan x = 8/3 = p/b

hence p =8 and b =3

find h by Pythagoras theorem...

h= √psq + bsq

h = √64+9

h = √73

sin x = p / h = 8/√73

hope it helps you

Answer 2

sinx = tanx * cosx

= tanx / secx

= tanx / √(tan^2x +1)

= (8/3) / √(64/9 + 1)

= (8/3) / √(73/9)

= 8 / √73 Ans....