Question

if tan x = a/b , show that $\frac{a sin x - b cos x}{a sin x + b cos x}$ =$\frac{a^2 - b^2}{a^2 + b^2}$

Answer 1

this is your answer,,hope it helps you

Answer 2

Answer:

L.H.S = R.H.S

Step-by-step explanation:

To show = a sin x - b cos x/ a sin x + b cos x = a² - b²/ a² + b²

Given, tan x = a/b

a sin x - b cos x/ a sin x + b cos x

Divide the numerator and denominator by cos x, we get.,

a tan x - b/ a tan x + b = a * (a/b) - b / a * (a/b) + b

= ((a² - b²)/b) / ((a² + b²)/b)

= (a² - b²/ a² + b²) = R.H.S