If tan x=b/a then find the value of (a^2+b^2)sin2x
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tan x = b/a
so b is height and a is base
so Hypotenuse by pythagoras will be
=a² + b²
Sin2x = 2 sinx cosx
= 2 × height / Hypotenuse × base × Hypotenuse
= 2 × a × b / (root(a²+b²))²
so putting in (a² + b²) Sin2x
(a²+b²) × 2 × a ×b / (a² + b²)
2ab answer
meanishasharma:
But the answer is 2ab
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7
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