If tan x = k tan y, show that ( k-1 )sin (x+y)=(k+1) sin (x-y)
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Answer:
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Step-by-step explanation:
tan x / tan y = k
(sinx/cosx)/(siny/cosy)=k
sixcosy/coxsiny=k
sinxcosy=kcosxsiny---(1)
LHS:
(k-1)sin(x+y)=(k-1)(sinxcosy+cosxsiny)=ksinxcosy+kcosxsiny-sinxcosy-cosxsiny
=ksinxcosy+sinxcosy-sinxcosy-cosxsiny[from(1)]
=ksinxcosy-cosxsiny
RHS:
(k+1)(sinxcosy-cosxsiny)
=ksinxcosy-kcosxsiny+sinxcosy-cosxsiny
=ksinxcosy-sinxcosy+sinxcosy-cosxsiny[from (1)]
=ksinxcosy-cosxsiny=LHS
so
LHS=RHS
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