If tan(x+y)=5/3 and tan(x-y)=7/23,find tan 2x?
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tan (x+y) = 5/3
tan(x-y) = 7/23
tan 2x = tan ( (x+y) + (x-y) )
therefore
tan 2x = tan(x+y) + tan (x-y) / 1 - tan(x+y) tan(x-y)
hence, tan 2x = 5/3 + 7/23 / 1 - 5/3 * 7/23
= 115+21/69 / 69-35/69
= 136/34
= 68/17.
therefore tan 2x = 68/17
tan(x-y) = 7/23
tan 2x = tan ( (x+y) + (x-y) )
therefore
tan 2x = tan(x+y) + tan (x-y) / 1 - tan(x+y) tan(x-y)
hence, tan 2x = 5/3 + 7/23 / 1 - 5/3 * 7/23
= 115+21/69 / 69-35/69
= 136/34
= 68/17.
therefore tan 2x = 68/17
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