If tan0 = 3/4 find the values of sec0 and cos0
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Step-by-step explanation:
given tan0=3/4=perpendicular/base
=using pyathgoreus theoram
hypotenuse"2=perpendicular"2+base"2
hypotnuse"2=3"2+4"2
hypotenuse"2=9+16=25
hypotnuse =5
now sec0=hypotnuse/base=5/4
also, cos0=base/hypotenuse=4/5
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