Question

if tan°=√3 then find the value of cosec^2°-cot^2° find the answer pls frnds​

Answer 1

Step-by-step explanation:

tanQ = √3

Q = π/6

now ,

cosec²π/6 - cot²π/6

(2/√3)² - (1/√3)²

4/3 - 1/3

3/3 = 1

Answer 2

Answer:

$5873 \alpha \beta \gamma e\pi \infty ln( log( log_{\% \binom{ \csc( \sec( \cot( \tan( \cos( \sin(5) ) ) ) ) ) }{7} }(5) ) )$

Step-by-step explanation:

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