Question

if tan0=4/3, find the value of: 4tan0-5cos0÷sec0+4cot0​

Answer 1

Step-by-step explanation:

tan0=4/3

cos0=3/5

sec0=5/3

cot0=3/4

$\frac{4( \frac{4}{3}) - 5( \frac{3}{5} ) }{ \frac{5}{3} + 4( \frac{3}{4} )}$

$\frac{ \frac{16}{3} - 3 }{ \frac{5}{3} + 3 }$

$\frac{ \frac{16 - 9}{3} }{ \frac{5 + 9}{3} }$

$\frac{7}{14}$

$\frac{1}{2}$