if tan0+cot0 =3then find the value of tan²0+cos²0
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Answer:
tanΘ + cotΘ = 3
squaring both the sides
(tanΘ + cotΘ)² = 3²
tan²Θ + cot²Θ + 2 × tanΘ × cotΘ = 9
tan²Θ + cot²Θ + 2 × tanΘ × 1/tanΘ = 9 [cotΘ = 1/tanΘ]
tan²Θ + cot²Θ + 2 = 9
tan²Θ + cot²Θ = 9 - 2
tan²Θ + cot²Θ = 7
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