Question

If tan1/2 evaluate 2 sin theta+3 cos theta ÷ 4 cos theta + 3 sin theta

Answer 1

Answer:

I don't know this answer

Answer 2

Given tanθ=1/2 ⇒sinθ/cosθ= 1/2.

Now (2sinθ+3cosθ)/(4cosθ+3sinθ)

Now (2sinθ+3cosθ)/(4cosθ+3sinθ)

= (2sinθ/cosθ +3cosθ/cosθ) / (4cosθ/cosθ + 3sinθ/cosθ)

( Multiplying by 1/cosθ with both numerator and denominator as cosθ is not equal to zero)

( Multiplying by 1/cosθ with both numerator and denominator as cosθ is not equal to zero)

= (2tanθ+3)/(4+3tanθ)

= (2*1/2 +3)/ (4+3*1/2)

= (1+3)/(4+3/2)

= (1+3)/(4+3/2)

=8/11