Question

if Tan11=Cot11 then value of acute angle ' 11 '.​

Answer 1

Answer:

tan11x=cot7x

⇒tan11x=tan(90°−7x)

⇒tan11x−tan(90°−7x)=0

⇒tan(11x−90°+7x)(1+tan11x.tan(90°−7x))=0

⇒tan(18x−90°)(1+tan11x.tan(90°−7x))=0

⇒tan(18x−90°)=0[∴1+tan11x.tan(90°−7x)

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=0]

⇒tan(10x−90°)=tan0°

⇒18x−90°=0

⇒18x=90°

⇒x=5°

Hence, the answer is 5°.

Step-by-step explanation:

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