if tan²=5/12 then find the value of sin theta cos theta+cos theta sec theta
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Step-by-step explanation:
tan²(theta)=5/12
tan(theta)=√(5/12)
therefore we get sin(theta)=√(5/17)
&cos(theta)=√(12/17)
sec(theta)=√(17/12)
therefore,
sin theta cos theta+cos there sec theta=
√(5/17)×√(12/17)+√(12/17)×√(17/12)
=√60/17+1. {because √(12/17)×√(17/12)=1}
taking L.C.M
=(√60+1)/17
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