Question

if tan²θ= 8/7 then find the value of (1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ)​

Answer 1

Answer:

The answer will be 7/8.

Step-by-step explanation:

(1+sinθ)(1-sinθ)/(1+cosθ)(1-cosθ)

(1-sin^2 θ)/(1-cos^2 θ) {(a-b)(a+b) = a^2-b^2}

cos^2 θ/sin^2 θ. {1-sin^2 θ=cos^2 θ and 1-cos^2 θ=sin^2 θ)

(cos θ/sin θ)^2

(cot θ)^2

(1/tan θ)^2

1/tan^2 θ

1/(8/7)

7/8

That's all.

Answer 2

Answer:

(1-sin theta) (1+sin theta) / (1-cos theta) (1+cos theta)

= 1-sin^2 theta/1-cos^2 theta

= cos^2 theta / sin^2 theta

= cot^2 theta

= 1/tan^2 theta

= 1/8\7

= ⅞ answer