Question

If tan2θ + cot2θ = 2, then what is the value of 2sec θ cosec θ?

A) 0 B) 1 C) 2 D) 4

Answer 1

sin⁡x/sin⁡〖y 〗 =p & cos⁡x/cos⁡y =q

sin⁡x/p=sin⁡y

⇒sin^2⁡x/p^2 =sin^2⁡y

cos⁡x/q=cos⁡〖y⇒cos^2⁡x/q^2 =cos^2⁡y 〗 , Adding both equation

sin^2⁡x/p^2 +cos^2⁡x/q^2 =sin^2⁡〖y+cos^2⁡〖y=1〗 〗 divide by cos^2⁡x

tan^2⁡x/p^2 +1/q^2 =1/cos^2⁡x

tan^2⁡〖x(1/p^2 -1)=1-1/q^2 〗 ,tan^2⁡〖x=((q^2-1)/q^2 )/((1-p^2)/p^2 )〗 tan⁡〖x=p/q √((q^2-1)/(1-p^2 ))〗

Therefore 0 is ur answer....

Answer 2

Answer:

Sin a = cos A

A is a correct

answer mark me as a brilliant plz