If tan2θ•tan4θ=1, find the value of tan3θ, where 0°<θ
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tan 2θ = cot 4θ (Given)
=> cot(90°-2θ) = cot 4θ
=> 90°-2θ = 4θ
=> 6θ = 90°
=> θ = 90°/6 = 15°
So, tan 3θ = tan (3×15°) = tan 45° = 1 [Ans]
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