Question

if tan20=cot(θ+6), then what is the value of θ?

Answer 1

Answer:

clearly,

tan2Ф = cot (Ф+6)

cot(90-2Ф) = cot (Ф+6)

90 - 2Ф = Ф+ 6

3Ф = 84

Ф = 28

Step-by-step explanation:

Answer 2

here is your answer

tan2θ = cot(θ+6)

tan2θ = cot(θ+6)cot(90-2θ) =cot ( θ+6)

tan2θ = cot(θ+6)cot(90-2θ) =cot ( θ+6)90-2θ = θ +6

tan2θ = cot(θ+6)cot(90-2θ) =cot ( θ+6)90-2θ = θ +63θ = 84

tan2θ = cot(θ+6)cot(90-2θ) =cot ( θ+6)90-2θ = θ +63θ = 84θ = 28