Question

If Tan20°=k then (Tan250°+Tan340°) /(Tan30°-Tan110°) =~

Answer 1

Step-by-step explanation:

given tan 20 = k----(1) tan 250 = tan (270-20) = cot 20 = 1/tan 20 = 1/k tan 340 = tan(360-20) = - tan 20 = -k tan 200 = tan (180+20) = tan 20 =k tan 110 = tan (90+20 ) = -cot 20 = -1/tan 20 = -1/k (tan 250 +tan 340) /( tan200 -tan 110) = (1/k -k)/(k + 1/k) = (1 -k²)/ (k²+1)

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