Question

If tan2A=cot(A-18)
Where 2A a Nun angle
Then learn the value of A?​

Answer 1

Answer:

Hope's this will help you..............

Answer 2

tan2A = cot(A-180°)

tan2A = -cot(180-A)

tan2A = -(-cotA)

tan2A = cotA

$\frac{2tanA}{1 - {tan}^{2} A} = \frac{1}{tanA} \\ 2 {tan}^{2}A = 1 - {tan}^{2} A \\ 3 {tan}^{2} A = 1 \\ {tan}^{2} A = \frac{1}{3} \\ tanA = ± \sqrt{ \frac{1}{3} } \\ A= \frac{\pi}{6} , \frac{5\pi}{6}$