If tan2A=cot(A-18)where 2A and A-18 are acute angle find the value of A
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Solution:
It is given that tan2A=cot(A−18°)
⇒tan2A=cot(90° −(108° −A))
⇒tan2A=tan(108° −A)
{°•° cot(90° −A)=tan(A)}
⇒2A=108° −A
⇒3A=108°
⇒A=108°/3 =36°
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