if tan2A=cot(A-18°), 2A is a quaternary angle then find value of A
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tan2A = cot( A-18)
cot(90-2A) = cot ( A- 18)
90-2A=A-18
90+18 = A+2A
108 = 3A
A =108/3
A = 36
cot(90-2A) = cot ( A- 18)
90-2A=A-18
90+18 = A+2A
108 = 3A
A =108/3
A = 36
vignesh007:
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