If tan2A=Cot(A-18°) Find the value of B
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0
⇒A=36
Step-by-step explanation:
Given tan2A=cot(A−18
0
)
⇒cot(90−2A)=cot(A−18
0
)[∵tanθ=cot(90−θ)]
Comparing angles we get
90−2A=A−18
⇒90+18=A+2A
⇒3A=108
⇒A=
3
108
⇒A=36
Answered by
0
answer
tan2A=cot(A-18)
tan45=cot45
or
tan30=cot60
or
tan60=cot30
or
tan0=cot90
or
tan90=cot0
by putting only one value in place of a or b
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