Question

If tan2A = cot(A-18°), where 2A is an acute angle, find the value of A. ​

Answer 1

Answer:

Step by step explanation

We are given that tan2A = cot(A-18°)

We can also write tan2A = cot(90°-2A)

cot ( 90°-2A) = cot(A-18°)

Since (90°-2A) and (A -18°) are both acute angles

=> 90°-2A = A-18°

=> A+2A = 90° +18°

=> 3A = 108°

=> A = 108° /3

=> A = 36°

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Answer 2

Step-by-step explanation:

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We know that,.

tan2A= cot(90°-2A)

Considering,

cot(90°-2A)= cot(A-18°)

90°-2A=A-18°

90°+18°=2A+A

108°=3A

A=108°/3

A=36°

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