If tan2A = cot(A-18°) , where 2A is an acute angle, find the value of A .
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Heya !!
tan2A = cot (A–18°)
=> cot (90°–2A) = cot (A–18°)
=> 90–2A = A – 18
=> 2A + A = 90 + 18
=> 3A = 108
=> A = 108 / 3
=> A = 36°
tan2A = cot (A–18°)
=> cot (90°–2A) = cot (A–18°)
=> 90–2A = A – 18
=> 2A + A = 90 + 18
=> 3A = 108
=> A = 108 / 3
=> A = 36°
Anonymous:
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both answers are same
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yea
Ya dear
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