Question

if tan2A = cot(A-18degree), where 2A is an acute angle, find the value of A

Answer 1

Hey !!!

tan2A = cot ( A - 18 )

where 2A is an acute angle hence

cotA (90° - 2A ) = cot ( A - 18 )

90° + 18 = 3A

A = 108/3 = 36°

Hence value of A = 36°

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Hope it helps you !!!

@Rajukumar111
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Answer 2

 Solution:

It is given that tan2A=cot(A−18°)

 ⇒tan2A=cot(90° −(108° −A))

⇒tan2A=tan(108° −A)        

{°•° cot(90° −A)=tan(A)}

 ⇒2A=108° −A

 ⇒3A=108°

 ⇒A=108°/3 =36°

Thanks ☺