if tan2A = cot(A-18degree), where 2A is an acute angle, find the value of A
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5
Hey !!!
tan2A = cot ( A - 18 )
where 2A is an acute angle hence
cotA (90° - 2A ) = cot ( A - 18 )
90° + 18 = 3A
A = 108/3 = 36°
Hence value of A = 36°
__________________________
Hope it helps you !!!
@Rajukumar111
tan2A = cot ( A - 18 )
where 2A is an acute angle hence
cotA (90° - 2A ) = cot ( A - 18 )
90° + 18 = 3A
A = 108/3 = 36°
Hence value of A = 36°
__________________________
Hope it helps you !!!
@Rajukumar111
Answered by
1
Solution:
It is given that tan2A=cot(A−18°)
⇒tan2A=cot(90° −(108° −A))
⇒tan2A=tan(108° −A)
{°•° cot(90° −A)=tan(A)}
⇒2A=108° −A
⇒3A=108°
⇒A=108°/3 =36°
Thanks ☺
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