Question

If tan2a=cota-18 where 2a is an acute angle findthe value ofa

Answer 1

tan2a=cota-18
or,sin/cos×2a-cota+18

Answer 2

 Solution:

It is given that tan2A=cot(A−18°)

 ⇒tan2A=cot(90° −(108° −A))

⇒tan2A=tan(108° −A)        

{°•° cot(90° −A)=tan(A)}

 ⇒2A=108° −A

 ⇒3A=108°

 ⇒A=108°/3 =36°

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