Question

If tan2A=cotB, then A+B=​

Answer 1

Step-by-step explanation:

2tan(A-B)=2{tanA-tanB/1+tanAtanB}

Given:tanA=2tanB+cotB

2tanA=tanB+tanB+1/tanBtanA-tanB={(tan^2B+1)/(tanB)

From 2tanAtanB=2tan^2B+1

Substitute 3 and 4 in 1

You get2tan(A-B)=2

{tan^2B+1)/(tanB)/2tan^2B+2}2tan(A-B)

={(tan^2B+1)/(tanB)/tan^2B+1}2tan(A-B)

=(1/tanB)2tan(A-B)=cotB