Question

If tan²A + sec A = 5, find cos A.​

Answer 1

tan^2A + sec A =5

sec^2A-1+secA=5

let secA be x

x^2-1+x=5

x^2+x-6=0

x^2-2x+3x-6=0

x(x-2)+3(x-2)=0

(x+3)(x-2)=0

x=3,2

secA=3,2

1/cosA=3,2

cosA=1/3,1/2

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Answer 2

Heya mate,

Answer:

1/2 or -1/3

Step-by-step explanation:

Ur explanation is in the pic.....

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