Question

If tan2A / (secA -­ 1)2 = x, then the value of x is

A) (1+cosec

Answer 1

Answer:

Thanks for your question

Answer 2

Here is your answer dear⛄

$= > \frac{ {Tan}^{2} A}{( {Sec \: A \: - \: 1})^{2} }$

$= > \frac{ {Sec \: A}^{2} }{(Sec \: A \: - \: 1) {}^{2} }$

$= > \frac{(Sec \: A \: - \: 1) \: (Sec \: A \: + \: 1)}{( {Sec \: A \: - \: 1})^{2} }$

❥ Cancel (Sec A - 1) and ²

$= > \frac{ \frac{1}{Cos \: A} \: + \: 1}{ \frac{1}{Cos \: A} \: - 1}$

$= > \frac{1 \: + \: \frac{Cos \: A}{Cos \: A} }{1 \: - \: \frac{Cos \: A}{Cos \: A} }$

❥ Cancel the denominators (Cos A)

$= = > \: \frac{1 \: + \: Cos \: A}{1 \: - \: Cos \: A}$

❤ $x \: = \: \frac{ 1 \: + \: Cos \: A}{ 1 \: - \: Cos \: A}$

$\huge\colorbox{cyan}{MysticalGiggles}$