Math, asked by HemavarshiniP156, 9 months ago

If tan2A - tan2B = x, then the value of x is

A) (sin2A - sin2B)/(cos2A cos2B) B) (sin2A sin2B)/(cos2A - cos2B) C) (sin2A + sin2B)/(cos2A cos2B) D) (sin2A sin2B)/(cos2A + cos2B)

Answers

Answered by Anonymous
0

Answer:

Given :-

  • If tan2A - tan2B = x,

To Find ;-

  • then the value of x is

Answer is (sin2A sin2B)/(cos2A + cos2B)

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