If tan2theta+cot2theta=2, theta is an acute angle, then tan3theta
+cot3theta is equal to________.
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Answer:
x = theta
tan^2x+cot^2x=2
tan^2x+1/tan^2x=2
tan^4x+1=2tan^2x
tan^4x-2tan^2x+1=0
(tan^2x-1)(tan^2x-1)=0
tan^2x=1
tanx=1
cotx=1
use sum of cubes formula
tan^3x+cot^3x
=(tanx+cotx)(tan^2x-tanxcotx+cot^2x)
=(1+1)(1-1+1)=2
please mark as a brainlist
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