Question

if tan2tita =cot(tita -18) where2tita is an acute angle then tita =
​

Answer 1

Answer:

θ=36°

Step-by-step explanation:

tan2θ=cot(θ-18°)

⇒cot(90°-2θ)=cot(θ-18°)

⇒90°-2θ=θ-18°

⇒108°=3θ

⇒θ=36°

Answer 2

Answer:

tan2Q=cot(Q-18) (given)

cot(90-2Q)=cot(Q-18) [ tanQ=cot(90-Q)]

90-2Q=Q-18

90+18=Q+2Q (transposing)

108=3Q

108/3 = Q

36 = Q

Hence Q=36 degrees.

Step-by-step explanation:

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