if tan3x tan3y= 1 then sin(x+y)=?
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Answered by
6
Solution
tan3x tan3y=1
=>tan3x=1/tan3y
=>tan3x=Cot3y
=>tan3x=tan(90°-3y)
=>3x=90°-3y [as, canceling'tan" function]
=>3x+3y=90°
=>3(x+y)=90°
=>(x+y)=90°/3
=>(x+y)=30°
now.......
sin(x+y)=sin30°
=1/2
Answered by
142
- Tan3x*tan3y = 1
- sin(x+y)
- when TanA×tanB = 1 than,, (A+B) = 90°
since ,
Tan3x × tan 3y = 1 = tanA × tanB
comparing we get,
→ A = 3x
→ B = 3y
Hence,
→ 3x + 3y = 90°
→ 3(x+y) = 90°
Dividing both sides by 3 we get,
_____________________________
Now ,
#BAL
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