If tanA=1/2 & tan B =1/3. Then what is the value of (A+B)
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Hi friend,
tan(A + B)
= tan A + tan B / 1 - tan A * tan B
= (1 / 2 + 1 / 3) / 1 - ( 1 / 2 * 1 / 3)
= (3 + 2 / 6) / (1 - 1 / 6)
= (5 / 6 ) / (5 / 6)
= 1
tan π / 4 = 1
Therefore, (A + B) = π / 4 , so (A+B) = 45°
Hope it helps you:)
tan(A + B)
= tan A + tan B / 1 - tan A * tan B
= (1 / 2 + 1 / 3) / 1 - ( 1 / 2 * 1 / 3)
= (3 + 2 / 6) / (1 - 1 / 6)
= (5 / 6 ) / (5 / 6)
= 1
tan π / 4 = 1
Therefore, (A + B) = π / 4 , so (A+B) = 45°
Hope it helps you:)
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