Question

If tanA=1/2 and tanB=1/3 then what is the value of 4A+4B=

Answer 1

Answer:

calculate for tan(A+B) as we know it is equal to tanA+tanB/(1-tanAtanB). Let X be the calculated value then find its inverse.

Answer 2

Answer:

Wkt: tan A = 1/2. ,tan=3\2

tan (A+B)= (tan A + tanB) \ (1-tanA tan B)

= (1\2 + 1\3) \ (1 - 1\2*1\3)

= (5/6) \ (5/6)

tan (A+B) = 1

A+B = tan^-¹ (1)

multiplying by 4 on both sides

4A + 4B. = 4