Question

If tanA=1/2,cotB=3 then A+B=?​

Answer 1

Answer:

45°

Step-by-step explanation:

tanA=1/2 and tanB = 1/3

tan(A+B) = (tanA+tanB)/(1-tamAtanB)

tan(A+B)= (1/2+1/3)/[1-(1/2)(1/3)]

= (5/6)/(5/6) =1

tan(A+B) = tan45°

So, A+B= 45°

Answer 2

Answer:

tana=1\2

cotB=3

tand=1

tanB=1\cotB

than

tanba=1\3