Math, asked by aasthat880, 10 months ago

If TanA = 1/√3 , find the value of sin3A

Answers

Answered by sidbhatj
3

Answer: 1

Step-by-step explanation:

tan inverse of 1√3 =30 because tan (30) = 1√3

A = 30.

sin3A = 3sinA - 4sin³A

sin 3*30 = 3*sin(30) - 4*sin³30

              = 3*(1/2) -4*(1/2)³

              = (3/2) - (1/2)

              = 2/2 = 1

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