If TanA = 1/√3 , find the value of sin3A
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Answer: 1
Step-by-step explanation:
tan inverse of 1√3 =30 because tan (30) = 1√3
A = 30.
sin3A = 3sinA - 4sin³A
sin 3*30 = 3*sin(30) - 4*sin³30
= 3*(1/2) -4*(1/2)³
= (3/2) - (1/2)
= 2/2 = 1
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