If tanA=1/3
Then find the value of 8-8sin squareA
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Tan A = 1/3
Opposite/Adjacent = 1/3
So hypothenuse = root 10 (Pythagoras theorem)
Sin A = 1/root 10
8 - 8sin^ A =
8 - 8 * (1/root 10)^2 =
8 - 8/10 =
8 - 4/5 =
36/5
Opposite/Adjacent = 1/3
So hypothenuse = root 10 (Pythagoras theorem)
Sin A = 1/root 10
8 - 8sin^ A =
8 - 8 * (1/root 10)^2 =
8 - 8/10 =
8 - 4/5 =
36/5
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