Question

if TanA = 1/root3 then value of Sin2A is :

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Answer 1

√3/2.

Sin2A = 2tanA/1+tan²

given :- tanA = 1/√3

so

sin2A = 2×1√3/1+ (1/√3)²

= 2/√3 ×3/4

= √3/2

Answer 2

Answer:

tanA = 1/√3

tan A = tan 30 °

= > A = 30 °

so, the value of sin 2A = sin 2 ×30°

= sin 60°

√3/2