if tanA=1/route3 then evaluate [cosecsquretheta -secsqurethet
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If tan A=1/root 3
A =30 degrees
cosec square 30=2x2=4
sec square 30=2/root 3 x 2/root 3=4/3
4-4/3=2 2/3
ANSWER=8/3
A =30 degrees
cosec square 30=2x2=4
sec square 30=2/root 3 x 2/root 3=4/3
4-4/3=2 2/3
ANSWER=8/3
Answered by
1
Answer :
Given,
tanA = 1/√3
⇒ tanA = tan30°
⇒ A = 30°
So, cosec²A - sec²A
= (cosecA)² - (secA)²
= (cosec30°)² - (sec30°)²
= 2² - (2/√3)²
= 4 - 4/3
= (12 - 4)/3
= 8/3
#MarkAsBrainliest
Given,
tanA = 1/√3
⇒ tanA = tan30°
⇒ A = 30°
So, cosec²A - sec²A
= (cosecA)² - (secA)²
= (cosec30°)² - (sec30°)²
= 2² - (2/√3)²
= 4 - 4/3
= (12 - 4)/3
= 8/3
#MarkAsBrainliest
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