Question

if tanA=1 then, find the values of sinA +cosA/secA+cosecA​

Answer 1

Solution :

Given tanA = 1

=> tan A = tan 45°

=> A = 45°

Now ,

i ) SinA + cos A

= sin 45 + cos 45

= 1/√2 + 1/√2

= 2/√2

= √2 ---( 1 )

ii ) secA + cosecA

= sec45 + cosec45

= √2 + √2

= 2√2 -----( 2 )

value of

(sinA+cosA)/(secA+cosecA)

= √2/(2√2)

= 1/2

•••••

Answer 2

Heya mate!!

Here's your answer!!

Since tanA = 1,

A = 45° ( tan45 = 1 )

Substituting A = 45° in the equation,

sin45 + cos45/sec45 + cosec45

=> (√2/2 + √2/2) /( 2/√2 + 2/√2)
=> (2√2/2)/(4/√2)
=> √2 /(2√2)
=> 1/2
=> 0.5

Hope it helps you!!

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